On Feb 5, 2013, at 12:28 PM, JACK SARFATTI <sarfatti@pacbell.net> wrote:

Thanks Nick. Keep up the good work. I hope to catch up with you on this soon. This may be a historic event of the first magnitude if the Fat Lady really sings this time and shatters the crystal goblet. On the Dark Side this may open Pandora's Box into a P.K. Dick Robert Anton Wilson reality with controllable delayed choice precognition technology. ;-)

On Feb 5, 2013, at 10:38 AM, nick herbert <quanta@cruzio.com> wrote:

Demetrios--

Looking over your wonderful paper I have detected one

inconsistency but it is not fatal to your argument.

On page 3 you drop two r terms because "alpha", the complex

amplitude of the coherent state can be arbitrarily large in

magnitude.

But on page 4 you reduce the magnitude of "alpha" so that

at most one photon is reflected. So now alpha cannot be

arbitrarily large in magnitude.

But this is just minor quibble in an otherwise superb argument.

This move does not affect your conclusion--which seems

to directly follow from application of the Feynman Rule: For distinguishable

outcomes, add probabilities; for indistinguishable outcomes, add amplitudes.

To help my own understanding of how your scheme works,

I have simplified your KISS proposal by replacing your coherent states with

the much simpler state |U> = x|0> + y|1>. I call this variation of your proposal KISS(U)

When this state |U> is mixed with the entangled states at the beamsplitters,

the same conclusion ensues: there are two |1>|1> results on Bob's side of the source

that cannot be distinguished -- and hence must be amplitude added.

The state |U> would be more difficult to prepare in the lab than a weak coherent state

but anything goes in a thought experiment. The main advantage of using state |U>

instead of coherent states is that the argument is simplified to its essence and needs

no approximations. Also the KISS(U) version shows that your argument is independent

of special properties possessed by coherent states such as overcompleteness and non-

orthogonality. The state |U> is both complete and orthogonal -- and works just as well

to prove your preposterous conclusion. --- that there is at least one way of making photon

measurements that violates the No-Signaling Theorem.

Thanks for injecting some fresh excitement into the FTL signaling conversation.

warm regards

Nick Herbert

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