Tuesday, February 5, 2013

On Feb 5, 2013, at 12:28 PM, JACK SARFATTI <sarfatti@pacbell.net> wrote:

Thanks Nick. Keep up the good work. I hope to catch up with you on this soon. This may be a historic event of the first magnitude if the Fat Lady really sings this time and shatters the crystal goblet. On the Dark Side this may open Pandora's Box into a P.K. Dick Robert Anton Wilson reality with controllable delayed choice precognition technology. ;-)

On Feb 5, 2013, at 10:38 AM, nick herbert <quanta@cruzio.com> wrote:


Looking over your wonderful paper I have detected one
inconsistency but it is not fatal to your argument.

On page 3 you drop two r terms because "alpha", the complex
amplitude of the coherent state can be arbitrarily large in

But on page 4 you reduce the magnitude of "alpha" so that
at most one photon is reflected. So now alpha cannot be
arbitrarily large in magnitude.

But this is just minor quibble in an otherwise superb argument.

This move does not affect your conclusion--which seems
to directly follow from application of the Feynman Rule: For distinguishable
outcomes, add probabilities; for indistinguishable outcomes, add amplitudes.

To help my own understanding of how your scheme works,
I have simplified your KISS proposal by replacing your coherent states with
the much simpler state |U> = x|0> + y|1>. I call this variation of your proposal KISS(U)

When this state |U> is mixed with the entangled states at the beamsplitters,
the same conclusion ensues: there are two |1>|1> results on Bob's side of the source
that cannot be distinguished -- and hence must be amplitude added.

The state |U> would be more difficult to prepare in the lab than a weak coherent state
but anything goes in a thought experiment. The main advantage of using state |U>
instead of coherent states is that the argument is simplified to its essence and needs
no approximations. Also the KISS(U) version shows that your argument is independent
of special properties possessed by coherent states such as overcompleteness and non-
orthogonality. The state |U> is both complete and orthogonal -- and works just as well
to prove your preposterous conclusion. --- that there is at least one way of making photon
measurements that violates the No-Signaling Theorem.

Thanks for injecting some fresh excitement into the FTL signaling conversation.

warm regards
Nick Herbert

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